Oracle 1z1-148 : Oracle Database: Advanced PL/SQL

  • Exam Code: 1z1-148
  • Exam Name: Oracle Database: Advanced PL/SQL
  • Updated: Sep 17, 2026
  • Q & A: 108 Questions and Answers

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Oracle 1z1-148 Exam Overview:

Certification Vendor:Oracle
Exam Name:Oracle Database 12c: Advanced PL/SQL
Exam Number:1Z0-148
Available Languages:English
Related Certifications:Oracle Database PL/SQL Developer Certified Associate
Oracle Database SQL Certified Associate
Real Exam Qty:Approximately 55
Exam Format:Multiple Response, Multiple Choice
Exam Price:$245 USD (may vary by region)
Passing Score:60%
Exam Duration:120 minutes
Recommended Training:Oracle University Training
Exam Registration:Oracle Certification Registration
Pearson VUE Oracle Exams
Sample Questions:Free Download 1z1-148 Exam PDF Torrent
Exam Way:Proctored exam via Pearson VUE (online or test center)
Pre Condition:Recommended: Oracle Database SQL Certified Associate or equivalent PL/SQL experience
Official Syllabus URL:https://education.oracle.com/oracle-certification

Oracle 1z1-148 Exam Syllabus Topics:

SectionObjectives
Topic 1: PL/SQL Fundamentals and Advanced Concepts- Advanced PL/SQL Programming
  • 1. Control structures and exception handling
    • 2. Advanced data types (records, collections)
      - Packages and Modularization
      • 1. Overloading and encapsulation
        • 2. Package specification and body design
          Topic 2: Advanced Database Features- Large Objects and Advanced Data Handling
          • 1. Collections and object types
            • 2. BLOB, CLOB handling
              - Triggers and Events
              • 1. INSTEAD OF triggers
                • 2. Row-level and statement-level triggers
                  Topic 3: Database Interaction and SQL Integration- Dynamic SQL
                  • 1. Dynamic query construction
                    • 2. EXECUTE IMMEDIATE usage
                      - SQL and PL/SQL optimization
                      • 1. Performance tuning techniques
                        • 2. Bulk processing with BULK COLLECT and FORALL

                          Oracle Database: Advanced PL/SQL Exam FAQ — Irresistible Answers

                          Recommended: Oracle Database SQL Certified Associate or equivalent PL/SQL experience Eligibility rules change over time, so verify the current requirements on the official page (official 1z1-148 exam page) before registering.

                          The Oracle Database: Advanced PL/SQL is Oracle's certification exam for Oracle Database 12c Advanced PL/SQL Developer Certified Professional, at the Professional level. Related credentials include Oracle Database SQL Certified Associate, Oracle Database PL/SQL Developer Certified Associate. Start simply: free demo first, full set when convinced.

                          Yes:

                          After any course, reinforce it with the 108 practice questions for the Oracle Database: Advanced PL/SQL — every answer expert-verified.

                          120 minutes for Approximately 55 questions. The VCETorrent engine simulates real examination conditions, so the pacing feels familiar before exam day.

                          Yes — download our demo freely as your reference; you may be impressed by the conciseness and clearness of the Oracle Database: Advanced PL/SQL exam VCE. Purchases include 365 days of free updates by email; renew afterward at 50% off.

                          The Oracle Database: Advanced PL/SQL blueprint spans 3 domains — including PL/SQL Fundamentals and Advanced Concepts, Database Interaction and SQL Integration, Advanced Database Features. Our material keeps close to this syllabus; the complete outline above lists every subtopic.

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                          Oracle Database: Advanced PL/SQL Sample Questions:

                          Question #1

                          Refer to the Exhibit.

                          Examine this procedure created in a session where PLSQL_OPTIMIZE_LEVEL =2:

                          PL/SQL tracing in enabled in a user session using this command:
                          EXEC DBMS_TRACE.SET_PLSQL_TRACE (DBMS_TRACE.TRACE_ENABLED_LINES)
                          The procedure is executed using this command:
                          EXEC PRC_1
                          Examine the exhibit for the content of the PLSQL_TRACE_EVENTS table.
                          Why is tracing excluded from the PLSQL_TRACE_EVENTS table?

                          • A. DBMS_TRACE.TRACE_ENABLED_LINES traces only exceptions in subprograms.
                          • B. PRC_1 is compiled with the default AUTHID DEFINER clause.
                          • C. Tracing will be enabled only for the second execution of PRC_1.
                          • D. PRC_1 is not compiled with debugging information.
                          • E. Tracing is not enabled with the TRACE_ENABLED_CALLS option.
                          Reveal Solution  Discussion  0

                          Correct Answer: D  🗳️

                          Question #2

                          Examine this code:

                          Which two are valid correlations to the code to avoid or mitigate SQL Injection?

                          • A. CREATE PROCEDURE list_products_dynamic (p_product_name VARCHAR2 DEFAULT NULL) ASTYPE cv_pordtyp IS REF CURSOR;cv cv_prodtyp;v_prodname prod_info.name%TYPE;v_listprice prod_info.price%TYPE;v_bind VARCHAR2 (400);BEGINv_bind := DBMS_ASSERT.ENQUOTE_LITERAL ('%' | | p_product_name | | '%');OPEN cv FOR 'SELECT name, price FROM prod_info WHERE name LIKE ' | | v_bind;LOOPFETCH cv INTO v_prodname, v_listprice;EXIT WHEN cv%NOTFOUND;DBMS_OUTPU.PUT_LINE ('Product Info: ' | | v_prodname | | ',' | | v_listprice);END LOOP;CLOSE cv;END;
                          • B. CREATE PROCEDURE list_products_dynamic (p_product_name VARCHAR2 DEFAULT NULL) ASTYPE cv_pordtyp IS REF CURSOR;cv cv_prodtyp;v_prodname prod_info.name%TYPE;v_listprice prod_info.price%TYPE;v_bind VARCHAR2 (400);BEGINv_bind := '%' | | p_product_name | |
                            '%';OPEN cv FOR 'SELECT name, price FROM prod_info WHERE name LIKE :b' USING v_bind;LOOPFETCH cv INTO v_prodname, v_listprice;EXIT WHEN cv%NOTFOUND;DBMS_OUTPU.PUT_LINE ('Product Info: ' | | v_prodname | | ',' | | v_listprice);END LOOP;CLOSE cv;END;
                          • C. CREATE PROCEDURE list_products_dynamic (p_product_name VARCHAR2 DEFAULT NULL) ASv_bind VARCHAR2 (400);BEGINv_bind := '%' | | p_prodname | | '%';FOR rec IN ('SELECT name, price FROM prod_info WHERE name like ' | | v_bind) LOOPDBMS_OUTPUT.PUT_LINE ('Product Info: ' | | rec.name | | ',' | | rec.price);END LOOP;END;
                          • D. CREATE PROCEDURE list_products_dynamic (p_product_name VARCHAR2 DEFAULT NULL) ASTYPE cv_pordtyp IS REF CURSOR;cv cv_prodtyp;v_prodname prod_info.name%TYPE;v_listprice prod_info.price%TYPE;v_bind VARCHAR2 (400);BEGINv_bind := '%' | | p_product_name | |
                            '%';OPEN cv FOR 'SELECT name, price FROM prod_info WHERE name LIKE ' | | v_bind;LOOPFETCH cv INTO v_prodname, v_listprice;EXIT WHEN cv%NOTFOUND;DBMS_OUTPU.PUT_LINE ('Product Info: ' | | v_prodname | | ',' | | v_listprice);END LOOP;CLOSE cv;END;
                          • E. CREATE PROCEDURE list_products_dynamic (p_product_name VARCHAR2 DEFAULT NULL) ASTYPE cv_pordtyp IS REF CURSOR;cv cv_prodtyp;v_prodname prod_info.name%TYPE;v_listprice prod_info.price%TYPE;v_bind VARCHAR2 (400);BEGINv_bind := '''%' | | p_product_name | |
                            '%''';OPEN cv FOR 'SELECT name, price FROM prod_info WHERE name LIKE ' | | v_bind;LOOPFETCH cv INTO v_prodname, v_listprice;EXIT WHEN cv%NOTFOUND;DBMS_OUTPU.PUT_LINE ('Product Info: ' | | v_prodname | | ',' | | v_listprice);END LOOP;CLOSE cv;END;
                          Reveal Solution  Discussion  0

                          Correct Answer: C,D  🗳️

                          Question #3

                          Examine this function:

                          Execute the query:
                          SELECT remap_schema FROM dual;
                          Which is the correct output from the query?

                          • A. CREATE TABLE "EMP" ("EMPNO" NUMBER (4, 0), "ENAME" VARCHAR2 (10), "JOB" VARCHAR2 (9), "MGR" NUMBER (4, 0), "HIREDATE" DATE, "SAL" NUMBER (7, 2), "COMM" NUMBER (7, 2), "DEPTNO" NUMBER (2, 0),CONSTRAINT "PK_EMP" PRIMARY KEY ("EMPNO")USING INDEX ENABLE,CONSTRAINT "FK_DEPTNO" FOREIGN KEY ("DEPTNO")REFERENCES "DEPT" ("DEPTNO") ENABLE)
                          • B. CREATE TABLE "EMP" ("EMPNO" NUMBER (4,0), "ENAME" VARCHAR2 (10), "JOB" VARCHAR2 (9), "MGR" NUMBER (4,0), "HIREDATE"DATE, "SAL" NUMBER (7,2) , "COMM" NUMBER (7,2), "DEPTNO" NUMBER (2,0),CONSTRAINT "PK_EMP" PRIMARY KEY ("EMPNO")USING INDEX PCTFREE 10 INITRANS 2 MAXTRANS 255STORAGE (INITIAL
                            65536 NEXT 1048576 MINEXTENTS 1 MAXEXTENTS 2417483645PCTINCREASE 0 FREELISTS
                            1 FREELIST GROUPS 1BUFFER_POOL DEFAULT FLASH_CHACHE DEFAULT
                            CELL_FLASH_CACHE DEFAULT)TABLESPACE "USERS" ENABLE,CONSTRAINT
                            "FK_DEPTNO" FOREIGN KEY ("DEPTNO")REFERENCES "DEPT" ("DEPTNO") ENABLE)
                            SEGMENT CREATION IMMEDIATEPCTFREE 10 PCTUSED 40 INITRANS 1 MAXTRANS
                            255NOCOMPRESS LOGGINGSTORAGE (INITIAL 65536 NEXT 1048576 MINEXTENTS 1
                            MAXEXTENTS 2147483645PCTINCREASE 0 FREELISTS 1 FREELIST GROUPS
                            1BUFFER_POOL DEFAULT FLASH_CACHE DEFAULT CELL_FLASH_CACHE
                            DEFAULT)TABLESPACE "USERS"
                          • C. CREATE TABLE "SCOTT". "EMP" ("EMPNO" NUMBER (4, 0), "ENAME" VARCHAR2 (10),
                            "JOB" VARCHAR2 (9), "MGR" NUMBER (4, 0), "HIREDATE" DATE, "SAL" NUMBER (7, 2),
                            "COMM" NUMBER (7, 2), "DEPTNO" NUMBER (2, 0),CONSTRAINT "PK_EMP" PRIMARY KEY ("EMPNO")USING INDEX ENABLE,CONSTRAINT "FK_DEPTNO" FOREIGN KEY ("DEPTNO")REFERENCES "DEPT" ("DEPTNO") ENABLE)
                          • D. CREATE TABLE "EMP" ("EMPNO" NUMBER (4,0), "ENAME" VARCHAR2 (10), "JOB" VARCHAR2 (9), "MGR" NUMBER (4,0), "HIREDATE"DATE, "SAL" NUMBER (7, 2) , "COMM" NUMBER (7, 2), "DEPTNO" NUMBER (2,0),CONSTRAINT "PK_EMP" PRIMARY KEY ("EMPNO")USING INDEX PCTFREE 10 INITRANS 2 MAXTRANS 255STORAGE (INITIAL
                            65536 NEXT 1048576 MINEXTENTS 1 MAXEXTENTS 2417483645PCTINCREASE 0 FREELISTS
                            1 FREELIST GROUPS 1BUFFER_POOL DEFAULT FLASH_CHACHE DEFAULT
                            CELL_FLASH_CACHE DEFAULT)TABLESPACE "SYSAUX" ENABLE,CONSTRAINT
                            "FK_DEPTNO" FOREIGN KEY ("DEPTNO")REFERENCES "DEPT" ("DEPTNO") ENABLE)
                            SEGMENT CREATION IMMEDIATEPCTFREE 10 PCTUSED 40 INITRANS 1 MAXTRANS
                            255NOCOMPRESS LOGGINGSTORAGE (INITIAL 65536 NEXT 1048576 MINEXTENTS 1
                            MAXEXTENTS 2147483645PCTINCREASE 0 FREELISTS 1 FREELIST GROUPS
                            1BUFFER_POOL DEFAULT FLASH_CACHE DEFAULT CELL_FLASH_CACHE
                            DEFAULT)TABLESPACE "SYSAUX"
                          Reveal Solution  Discussion  0

                          Correct Answer: A  🗳️

                          Question #4

                          Which two can be used to find details of parameters for overloaded PL/SQL routines?

                          • A. ALL_DESCRIBE
                          • B. ALL_PROCEDURES
                          • C. ALL_SOURCE
                          • D. ALL-DEPENDENCIES
                          • E. ALL_ARGUMENTS
                          Reveal Solution  Discussion  0

                          Correct Answer: C,E  🗳️

                          Question #5

                          In which situation will cached results become invalid?

                          • A. When a session on this database instance invokes the function with the same parameter values
                          • B. When a session executes an insert, update, or delete statement on a table or view that is queried by the result-cached function
                          • C. When the memory allocated to the server result cache is increased using the RESULT_CACHE_MAX_SIZE initialization parameter
                          • D. When the RESULT_CACHE_MODE parameter is set to FORCE.
                          • E. When a new session is opened to invoke the function which is already cached
                          Reveal Solution  Discussion  0

                          Correct Answer: B  🗳️

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